Originally posted by ScottK:
Close but not quite - the force of gravity decreases with the square of the distance between the 2 objects F = G m1 * m2 / r^2. While relatively small, gavity would be less on the top of Everst compared to sea level. For the g force acceleration g= G m / r2 where r and m are the mass and radius of the earth. g has the value of 9.78039 x 10-1 m.s-2 at the equator and 9.83217 x 10-1 m.s-2 at the poles (since the earth is somewhat flattened at the poles). Diff would be bigger on everst 
C'mon Scott, this is Intro to Physics 100A- save your advanced, real-world calculations for Vectors/Statics 400! 
-Chuck Dienzo
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"If trees could scream, would we be so cavalier about cutting them down? We might, if they screamed all the time, for no good reason."
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