Ok, I took Math/calc etc. ( Seems like years back) Now my understanding of this after playing with numbers is that R is the resistence in the wire not the amps load impedence. Do this one 80 amps of current at 1 ohm, according to your interpretation you need 80V for it to be possible(80=80*1) I think we all know most true 800-1000 watt class AB amps will draw this amount. Now figure 14V with 80 amps R=.175 Ohms. So you going to say that in order for an amp to draw 80 amps it has to be at .175 Ohm! I think there is a more advanced law that has efficiency figured in. I haven't looked for it yet, most likely will be in my calculator as well (HP 48G)
Maybe I am wrong and dont remember math at all but something does not seem right.
