I could kinda see where he would think that. At this power, it takes so many hp to rotate the drivetrain so it should still take the same amount of power to rotate it even with more over-all hp. But, he is wrong.
95 SE Modded - Gone
98 E0 Black SVT - Gone
98 se sport - Broken
00 T-Red SVT - Nice
If you want to try to realize WHY it is a percentage rather than a fixed number you have to think about viscosity of liquids. There is the oil in the engine bearings, the transmission oil and if ATX a torque converter.
If you picture stirring a pot of honey slowly you have a fixed amount of effort required. Now increase the speed that you stir it and your drag will go up making it harder and harder to stir the faster you go. A car driving on the road below 55-60mph experiences little power loss through wind resistance. Going up to just 75mph requires significantly more power with the losses going up exponentially until you reach a maximum speed. The viscosity of the liquid determines the losses. In the atx the torque converter is basically two fans suspended in liquid that oppose each other. when the first fan turns it forces the liquid towards the other fan, causing it to move. At slow rpm the fan pushes the liquid but the liquid "slips" around the blades...slippage. This is the nature of the %loss from power.
warmonger
Former owner of '99 CSVT - Silver #222/2760
356/334 wHP/TQ at 10psi on pump gas!
See My Mods
'05 Volvo S40 Turbo 5 AWD with 6spd, Passion Red
'06 Mazda5 Touring, 5spd,MTX, Black
Originally posted by GreenNuggs: I'll admit, I didn't really do any owning. Actually, DuratecTour did most of it.
Sorry to jump in on your owning . There's a lot of misinformation floating around over there, but what do you expect from a buncha people who will fight to the death that their precious Mazda isn't some "POS Ford" .
Originally posted by DemonSVT: Standard accepted loss with the MTX-75 on our platform is 17-18% HP and 9-10% TQ
Now you must remember you can not add this amount from the wheel power levels to make the crank HP. Mathematics just does not work that way! You have to divide by the remaining percentage.
Hector
2003 Rally Red Mitsubishi Evolution VIII
257HP/259TQ
2005 Lapis Blue Mazda 6s
RET: 00 Cabernet Red Ford Contour Zetec ATX SUPERCHARGED
160HP/141TQ
There is no magical number for drivetrain loss. For every car it is different, even for identical makes and models. There's too many variables to try and guess a %.
BTW what DemonSVT said is correct. There is another way that is maybe a little easier:
Wheel HP * (1 + drivetrain loss %) = Crank HP
Example:
150whp * (1.10) = 165bhp
Isn't math fun?
Dan
Acura Integra GS-R w/mods
Former owner of a 95 SE
. There's a lot of misinformation floating around over there, but what do you expect from a buncha people who will fight to the death that their precious Mazda isn't some "POS Ford" 
. 
