Originally posted by warmonger:
If you assume 90% VE at the point on the dyno where the torque curve is highest, e.g.
150 ft-lbs at highest peaks is 90% then (VEmax*0.9=150)
VEmax=167ft-lbs
then say you start at 2000 rpm with 125ft-lbs, you would have 125/167= ~0.75 or 75%
So you plug in numbers for the variable (VEmax) that when put through the equation gives you peak TQ read on the dyno. Then the quotient of TQ at 2K RPM and peak TQ gives you average VE. Correct? Also, is .9 the assumed 90%
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