Originally posted by JEDsContour:
1. If you could actually pressurize a 2.5L intake to 100psi, what would the effective displacement of the engine be, or in other words, how "big" would a naturally aspirated engine have to be to consume the same mass of air/fuel mixture? Go ahead and assume room temperature air for this fantasy engine.



1. Too many variables. Pressurizing the intake to a specific PSI is one thing. But CFM flow to the engine because of it is another story altogether.

If you mean raising the cylinder pressure to roughly 6.8 atmospheres (14.7psi natural plus 85.3psi "forced" ) then that's your answer. 6.8 x 2.5 = 17 liters of effective displacement. Provided of course the temperature doesn't change. (100% efficient intercooler - hey this is a fantasy setup )

However this is only applicable if the engine is being force fed. Like discussed previously just shooting air into the intake does nothing because CFM draw is dictated by the engine's displacement and volumetric efficiency.


Quote:

How about at 6 and 9 and 12 and 15 psi (practical pressures)?
2. What if the pressurized air is at 200 Fahrenheit?
3. as opposed to 100 deg F for naturally aspirated?


1. Just derivations of the previous calculation. Provided if you meant 6, 9, 12, & 15 psi "above" normal atmospheric pressure of course.

2. BOOM! Detonation is a biotch...

3. Air density drops as temperature rises. How in-depth do you want this fantasy formula? It's late and I really don't want to break out my old physics books.

2000 SVT #674 13.47 @ 102 - All Motor! It was not broke; Yet I fixed it anyway.