Originally posted by JEDsContour:
Here's a quizz. If you could actually pressurize a 2.5L intake to 100psi, what would the effective displacement of the engine be, or in other words, how "big" would a naturally aspirated engine have to be to consume the same mass of air/fuel mixture? Go ahead and assume room temperature air for this fantasy engine.
How about at 6 and 9 and 12 and 15 psi (practical pressures)?
What if the pressurized air is at 200 Farenheit? as opposed to 100 deg F for naturally aspirated?
I'll post some answers if no one else does.
No takers yet?
This is a cumbersome experimental way of getting the answer:
Look at the contour V6 engine as simply an air pump. If you attach a balloon to the exhaust and rotate the engine crankshaft slowly through two revolutions, you will collect 2.5L of air in the balloon.
If you do this inside a big tank of air compressed to 100psi, you will still collect 2.5L of air. Now reduce the pressure in the tank to 0psi and measure the balloon volume after it expands fully â?? this is the number we want, the effective displacement.
You could modify the experiment to take temperature into consideration (for example 100degF at 0psi, 200degF at 12psi). Remember that air temperature increases when it is compressed (PV=nRT). Heat the compressed air tank to the temperature you are interested and rotate the crankshaft twice. Now release the pressure and measure the balloon volume after it has both fully expanded and cooled to the outside air temperature.
Anyone want to take a crack at calculating the kind of volumes you would measure?
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