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Whats the calculation to see how many watts a certain gauge wire can hold? I'm trying to figure out what gauge wire is needed to carry 350ish watts 10 feet (max). Thanks!

David


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Calculate maximum current required (current = power/voltage) and look up the gauge required in a table.


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Now, to calculate your required size MAIN power wire, you need the following:

Wire Gauge? (AWG)
Length of Wire? Feet
Total Amplifier Power? Watts
Amplifier Efficiency? %
Charging System Voltage? Volts


Assuming you are using a class AB amp (50-60% efficiency of power), a steady battery voltage of 13.8V, a wire length of ten feet, and total power at 350W (50-60% eff.) you would have the following:


Resistance/foot: 0.000629 Ohms
Total Resistance: 0.006292 Ohms
Voltage Drop: 0.266 Volts
(well below the accepted half volt drop maximum.)

Current Flow: 42.3 Amps
Circular Mils: 16483 (Keep at > 300 per foot of wire per amp)

Power Drawn From Charging System: 583 Watts total.




check out this calculator.. enter wattages for up to 4 amps, their effeciency, and system voltages, etc.. it calculates everything else.. the yellow text is calculations.
System Design Assistant


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I'm trying to use those calculators but I dont' know if I'm reading them right or using them right. Basically i want to know how many watts a 10 gauge wire can care 10 feet from a roughly 13 volt source. And i guess how many an 8 gauge can carry ets. The amp would have a maximum draw of around 350 @ 12 volts (i guess thats how to say it) so i'm wondering if the current 10 gauge wire in a car can support that amp.

David

oh and it's a class D amp

Last edited by BCSVT; 01/03/06 01:35 AM.

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Having entered a 13volt source, 10 foot main wire, and 350W's on the top amp (clicking Class D to select that class) and hitting enter..

I get that the minimum wire gauge would be 10awg.

Switching to 8AWG would be recommended at somewhere around the 525-550W range (when leaving ALL of the other variables the same.)



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oh ok, i see it now, awsome. Thanks for the help!


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